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13236840245129 is a prime number
BaseRepresentation
bin1100000010011111000100…
…1010010010011110001001
31201212102121011012120110012
43000213301022102132021
53213333022100321004
644052530453001305
72534221145435024
oct300476112223611
951772534176405
1013236840245129
114243792264376
12159947b023235
137502c853c5b7
1433a948ba41bb
1517e4c1ee446e
hexc09f1292789

13236840245129 has 2 divisors, whose sum is σ = 13236840245130. Its totient is φ = 13236840245128.

The previous prime is 13236840245051. The next prime is 13236840245131. The reversal of 13236840245129 is 92154204863231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9797669995129 + 3439170250000 = 3130123^2 + 1854500^2 .

It is a cyclic number.

It is not a de Polignac number, because 13236840245129 - 240 = 12137328617353 is a prime.

Together with 13236840245131, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13236840245329) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6618420122564 + 6618420122565.

It is an arithmetic number, because the mean of its divisors is an integer number (6618420122565).

Almost surely, 213236840245129 is an apocalyptic number.

It is an amenable number.

13236840245129 is a deficient number, since it is larger than the sum of its proper divisors (1).

13236840245129 is an equidigital number, since it uses as much as digits as its factorization.

13236840245129 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2488320, while the sum is 50.

The spelling of 13236840245129 in words is "thirteen trillion, two hundred thirty-six billion, eight hundred forty million, two hundred forty-five thousand, one hundred twenty-nine".