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13237862400041 is a prime number
BaseRepresentation
bin1100000010100010111000…
…0101100000000000101001
31201212112020101120102101112
43000220232011200000221
53213342120233300131
644053220125200105
72534255366551346
oct300505605400051
951775211512345
1013237862400041
11424416723a4a4
121599705400035
1375042c2359a6
1433aa0483b7cd
1517e531b0002b
hexc0a2e160029

13237862400041 has 2 divisors, whose sum is σ = 13237862400042. Its totient is φ = 13237862400040.

The previous prime is 13237862399989. The next prime is 13237862400043. The reversal of 13237862400041 is 14000426873231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13212388963225 + 25473436816 = 3634885^2 + 159604^2 .

It is an emirp because it is prime and its reverse (14000426873231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13237862400041 - 230 = 13236788658217 is a prime.

Together with 13237862400043, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13237862400043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6618931200020 + 6618931200021.

It is an arithmetic number, because the mean of its divisors is an integer number (6618931200021).

Almost surely, 213237862400041 is an apocalyptic number.

It is an amenable number.

13237862400041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13237862400041 is an equidigital number, since it uses as much as digits as its factorization.

13237862400041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 193536, while the sum is 41.

The spelling of 13237862400041 in words is "thirteen trillion, two hundred thirty-seven billion, eight hundred sixty-two million, four hundred thousand, forty-one".