Base | Representation |
---|---|
bin | 111101101001010000… |
… | …1010001001000000111 |
3 | 110122200212010022001122 |
4 | 1323102201101020013 |
5 | 4132104011031033 |
6 | 140452011144155 |
7 | 12364344360353 |
oct | 1732241211007 |
9 | 418625108048 |
10 | 132380955143 |
11 | 51162663a58 |
12 | 217a614505b |
13 | c639252a28 |
14 | 659b7ac463 |
15 | 369bdc6a98 |
hex | 1ed2851207 |
132380955143 has 2 divisors, whose sum is σ = 132380955144. Its totient is φ = 132380955142.
The previous prime is 132380955139. The next prime is 132380955151. The reversal of 132380955143 is 341559083231.
It is a weak prime.
It is an emirp because it is prime and its reverse (341559083231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132380955143 - 22 = 132380955139 is a prime.
It is a super-3 number, since 3×1323809551433 (a number of 34 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132380955094 and 132380955103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132380955193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66190477571 + 66190477572.
It is an arithmetic number, because the mean of its divisors is an integer number (66190477572).
Almost surely, 2132380955143 is an apocalyptic number.
132380955143 is a deficient number, since it is larger than the sum of its proper divisors (1).
132380955143 is an equidigital number, since it uses as much as digits as its factorization.
132380955143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 388800, while the sum is 44.
The spelling of 132380955143 in words is "one hundred thirty-two billion, three hundred eighty million, nine hundred fifty-five thousand, one hundred forty-three".
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