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132397258537 is a prime number
BaseRepresentation
bin111101101001101111…
…1011101011100101001
3110122201222210121010001
41323103133131130221
54132122144233122
6140453352423001
712364633062205
oct1732337353451
9418658717101
10132397258537
1151170889a35
12217ab6a7a61
13c63c7406cb
14659da13b05
15369d547527
hex1ed37dd729

132397258537 has 2 divisors, whose sum is σ = 132397258538. Its totient is φ = 132397258536.

The previous prime is 132397258457. The next prime is 132397258571. The reversal of 132397258537 is 735852793231.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 91472373136 + 40924885401 = 302444^2 + 202299^2 .

It is a cyclic number.

It is not a de Polignac number, because 132397258537 - 211 = 132397256489 is a prime.

It is a super-2 number, since 2×1323972585372 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (132397258577) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66198629268 + 66198629269.

It is an arithmetic number, because the mean of its divisors is an integer number (66198629269).

Almost surely, 2132397258537 is an apocalyptic number.

It is an amenable number.

132397258537 is a deficient number, since it is larger than the sum of its proper divisors (1).

132397258537 is an equidigital number, since it uses as much as digits as its factorization.

132397258537 is an evil number, because the sum of its binary digits is even.

The product of its digits is 9525600, while the sum is 55.

The spelling of 132397258537 in words is "one hundred thirty-two billion, three hundred ninety-seven million, two hundred fifty-eight thousand, five hundred thirty-seven".