Base | Representation |
---|---|
bin | 11110000110101011100111… |
… | …010110001000100000110111 |
3 | 122100210100221111120012111101 |
4 | 132012223213112020200313 |
5 | 114323222303030033211 |
6 | 1145331545253550531 |
7 | 36613423613243044 |
oct | 3606534726104067 |
9 | 570710844505441 |
10 | 132400543205431 |
11 | 39206833a67716 |
12 | 12a24142045447 |
13 | 58b5418b59507 |
14 | 249a3130121cb |
15 | 10490969be5c1 |
hex | 786ae7588837 |
132400543205431 has 2 divisors, whose sum is σ = 132400543205432. Its totient is φ = 132400543205430.
The previous prime is 132400543205423. The next prime is 132400543205509. The reversal of 132400543205431 is 134502345004231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132400543205431 - 23 = 132400543205423 is a prime.
It is a super-2 number, since 2×1324005432054312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132400541205431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66200271602715 + 66200271602716.
It is an arithmetic number, because the mean of its divisors is an integer number (66200271602716).
Almost surely, 2132400543205431 is an apocalyptic number.
132400543205431 is a deficient number, since it is larger than the sum of its proper divisors (1).
132400543205431 is an equidigital number, since it uses as much as digits as its factorization.
132400543205431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 132400543205431 its reverse (134502345004231), we get a palindrome (266902888209662).
The spelling of 132400543205431 in words is "one hundred thirty-two trillion, four hundred billion, five hundred forty-three million, two hundred five thousand, four hundred thirty-one".
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