Base | Representation |
---|---|
bin | 111101101001110111… |
… | …0001000010111110101 |
3 | 110122202021000222121102 |
4 | 1323103232020113311 |
5 | 4132124140314443 |
6 | 140454011055445 |
7 | 12365010550436 |
oct | 1732356102765 |
9 | 418667028542 |
10 | 132401104373 |
11 | 51172a7640a |
12 | 217b0a41585 |
13 | c640489055 |
14 | 65a033548d |
15 | 369da56cb8 |
hex | 1ed3b885f5 |
132401104373 has 2 divisors, whose sum is σ = 132401104374. Its totient is φ = 132401104372.
The previous prime is 132401104351. The next prime is 132401104441. The reversal of 132401104373 is 373401104231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 83658620644 + 48742483729 = 289238^2 + 220777^2 .
It is an emirp because it is prime and its reverse (373401104231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132401104373 - 224 = 132384327157 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132401104313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66200552186 + 66200552187.
It is an arithmetic number, because the mean of its divisors is an integer number (66200552187).
Almost surely, 2132401104373 is an apocalyptic number.
It is an amenable number.
132401104373 is a deficient number, since it is larger than the sum of its proper divisors (1).
132401104373 is an equidigital number, since it uses as much as digits as its factorization.
132401104373 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 29.
The spelling of 132401104373 in words is "one hundred thirty-two billion, four hundred one million, one hundred four thousand, three hundred seventy-three".
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