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13240124013 = 34413374671
BaseRepresentation
bin11000101010010110…
…00100001001101101
31021011201121222200110
430111023010021231
5204103432432023
610025445450233
7646050124434
oct142513041155
937151558613
1013240124013
115684783156
122696110979
13133006710c
148d85d411b
15527584a93
hex3152c426d

13240124013 has 4 divisors (see below), whose sum is σ = 17653498688. Its totient is φ = 8826749340.

The previous prime is 13240123987. The next prime is 13240124021. The reversal of 13240124013 is 31042104231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13240124013 - 213 = 13240115821 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13240124813) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2206687333 + ... + 2206687338.

It is an arithmetic number, because the mean of its divisors is an integer number (4413374672).

Almost surely, 213240124013 is an apocalyptic number.

It is an amenable number.

13240124013 is a deficient number, since it is larger than the sum of its proper divisors (4413374675).

13240124013 is an equidigital number, since it uses as much as digits as its factorization.

13240124013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4413374674.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 13240124013 its reverse (31042104231), we get a palindrome (44282228244).

The spelling of 13240124013 in words is "thirteen billion, two hundred forty million, one hundred twenty-four thousand, thirteen".

Divisors: 1 3 4413374671 13240124013