Base | Representation |
---|---|
bin | 1100000010101011010111… |
… | …0111001010100000001000 |
3 | 1201212202010010220221002112 |
4 | 3000222311313022200020 |
5 | 3213411301411441204 |
6 | 44054234141321452 |
7 | 2534366010006350 |
oct | 300526567124010 |
9 | 51782103827075 |
10 | 13240140343304 |
11 | 4245126065a36 |
12 | 159a040266288 |
13 | 750703157504 |
14 | 33ab7d1a7b60 |
15 | 17e616ab626e |
hex | c0ab5dca808 |
13240140343304 has 32 divisors (see below), whose sum is σ = 28373736216000. Its totient is φ = 5673944479680.
The previous prime is 13240140343301. The next prime is 13240140343319. The reversal of 13240140343304 is 40334304104231.
It is not an unprimeable number, because it can be changed into a prime (13240140343301) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7562702 + ... + 9147389.
It is an arithmetic number, because the mean of its divisors is an integer number (886679256750).
Almost surely, 213240140343304 is an apocalyptic number.
13240140343304 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
13240140343304 is an abundant number, since it is smaller than the sum of its proper divisors (15133595872696).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13240140343304 is a wasteful number, since it uses less digits than its factorization.
13240140343304 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16724253 (or 16724249 counting only the distinct ones).
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 13240140343304 its reverse (40334304104231), we get a palindrome (53574444447535).
The spelling of 13240140343304 in words is "thirteen trillion, two hundred forty billion, one hundred forty million, three hundred forty-three thousand, three hundred four".
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