132401413441 has 4 divisors (see below), whose sum is σ = 144437905584. Its totient is φ = 120364921300.

The previous prime is 132401413411. The next prime is 132401413451. The reversal of 132401413441 is 144314104231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 132401413441 - 2⁹ = 132401412929 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132401413411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6018246055 + ... + 6018246076.

It is an arithmetic number, because the mean of its divisors is an integer number (36109476396).

Almost surely, 2^132401413441 is an apocalyptic number.

132401413441 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

132401413441 is a deficient number, since it is larger than the sum of its proper divisors (12036492143).

132401413441 is a wasteful number, since it uses less digits than its factorization.

132401413441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12036492142.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 132401413441 its reverse (144314104231), we get a palindrome (276715517672).

The spelling of 132401413441 in words is "one hundred thirty-two billion, four hundred one million, four hundred thirteen thousand, four hundred forty-one".