Base | Representation |
---|---|
bin | 11110000110101101000101… |
… | …010101010010110000100011 |
3 | 122100210112000101122212202101 |
4 | 132012231011111102300203 |
5 | 114323234020212343210 |
6 | 1145332405543031231 |
7 | 36613510651164535 |
oct | 3606550525226043 |
9 | 570715011585671 |
10 | 132402120043555 |
11 | 3920747305951a |
12 | 12a2450213b517 |
13 | 58b560a74291b |
14 | 249a4225d7855 |
15 | 104913a145a3a |
hex | 786b45552c23 |
132402120043555 has 32 divisors (see below), whose sum is σ = 161704255003200. Its totient is φ = 104055096176640.
The previous prime is 132402120043513. The next prime is 132402120043577. The reversal of 132402120043555 is 555340021204231.
It is a happy number.
It is not a de Polignac number, because 132402120043555 - 211 = 132402120041507 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 664593039 + ... + 664792231.
It is an arithmetic number, because the mean of its divisors is an integer number (5053257968850).
Almost surely, 2132402120043555 is an apocalyptic number.
132402120043555 is a deficient number, since it is larger than the sum of its proper divisors (29302134959645).
132402120043555 is a wasteful number, since it uses less digits than its factorization.
132402120043555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 208311.
The product of its (nonzero) digits is 144000, while the sum is 37.
Adding to 132402120043555 its reverse (555340021204231), we get a palindrome (687742141247786).
The spelling of 132402120043555 in words is "one hundred thirty-two trillion, four hundred two billion, one hundred twenty million, forty-three thousand, five hundred fifty-five".
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