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1324040142400 = 26524575993023
BaseRepresentation
bin10011010001000110111…
…100010011111001000000
311200120120122010012221121
4103101012330103321000
5133143113234024100
62452131115202024
7164441643342163
oct23210674237100
94616518105847
101324040142400
11470582162a78
12194736446314
1397b1980a081
1448126273ada
15246946e551a
hex13446f13e40

1324040142400 has 168 divisors, whose sum is σ = 3271628102400. Its totient is φ = 527400407040.

The previous prime is 1324040142389. The next prime is 1324040142409. The reversal of 1324040142400 is 42410404231.

It is a super-2 number, since 2×13240401424002 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is not an unprimeable number, because it can be changed into a prime (1324040142409) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 437987289 + ... + 437990311.

It is an arithmetic number, because the mean of its divisors is an integer number (19473976800).

Almost surely, 21324040142400 is an apocalyptic number.

1324040142400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1324040142400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1635814051200).

1324040142400 is an abundant number, since it is smaller than the sum of its proper divisors (1947587960000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1324040142400 is a wasteful number, since it uses less digits than its factorization.

1324040142400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4101 (or 4086 counting only the distinct ones).

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 1324040142400 its reverse (42410404231), we get a palindrome (1366450546631).

The spelling of 1324040142400 in words is "one trillion, three hundred twenty-four billion, forty million, one hundred forty-two thousand, four hundred".