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1324041333973 is a prime number
BaseRepresentation
bin10011010001000111000…
…000110110110011010101
311200120120201100202110221
4103101013000312303111
5133143114040141343
62452131200514341
7164441656434151
oct23210700666325
94616521322427
101324041333973
114705828a7246
1219473691b9b1
1397b19b36547
14481264a4061
152469487d5ed
hex13447036cd5

1324041333973 has 2 divisors, whose sum is σ = 1324041333974. Its totient is φ = 1324041333972.

The previous prime is 1324041333959. The next prime is 1324041333991. The reversal of 1324041333973 is 3793331404231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 945548146449 + 378493187524 = 972393^2 + 615218^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1324041333973 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1324041333073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662020666986 + 662020666987.

It is an arithmetic number, because the mean of its divisors is an integer number (662020666987).

Almost surely, 21324041333973 is an apocalyptic number.

It is an amenable number.

1324041333973 is a deficient number, since it is larger than the sum of its proper divisors (1).

1324041333973 is an equidigital number, since it uses as much as digits as its factorization.

1324041333973 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 489888, while the sum is 43.

The spelling of 1324041333973 in words is "one trillion, three hundred twenty-four billion, forty-one million, three hundred thirty-three thousand, nine hundred seventy-three".