Base | Representation |
---|---|
bin | 1100000010101100100010… |
… | …0000110001101100110101 |
3 | 1201212202220221200210221021 |
4 | 3000223020200301230311 |
5 | 3213412422012213103 |
6 | 44054325200021141 |
7 | 2534406526416421 |
oct | 300531040615465 |
9 | 51782827623837 |
10 | 13240453241653 |
11 | 424527674a110 |
12 | 159a1090017b1 |
13 | 750752c20171 |
14 | 33abac977b81 |
15 | 17e6342c1bbd |
hex | c0ac8831b35 |
13240453241653 has 32 divisors (see below), whose sum is σ = 15665260861440. Its totient is φ = 11061870946560.
The previous prime is 13240453241651. The next prime is 13240453241677. The reversal of 13240453241653 is 35614235404231.
It is a cyclic number.
It is not a de Polignac number, because 13240453241653 - 21 = 13240453241651 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13240453241651) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4854175 + ... + 7074172.
It is an arithmetic number, because the mean of its divisors is an integer number (489539401920).
Almost surely, 213240453241653 is an apocalyptic number.
It is an amenable number.
13240453241653 is a deficient number, since it is larger than the sum of its proper divisors (2424807619787).
13240453241653 is a wasteful number, since it uses less digits than its factorization.
13240453241653 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11928537.
The product of its (nonzero) digits is 1036800, while the sum is 43.
Adding to 13240453241653 its reverse (35614235404231), we get a palindrome (48854688645884).
The spelling of 13240453241653 in words is "thirteen trillion, two hundred forty billion, four hundred fifty-three million, two hundred forty-one thousand, six hundred fifty-three".
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