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132411132000 = 25335372131191
BaseRepresentation
bin111101101010001010…
…0011000100001100000
3110122202221220102221000
41323110110120201200
54132134222211000
6140455010032000
712365162023500
oct1732424304140
9418687812830
10132411132000
11511786a5304
12217b4278600
13c64258a364
1465a17c5a00
15369e888000
hex1ed4518860

132411132000 has 1152 divisors, whose sum is σ = 567904296960. Its totient is φ = 29877120000.

The previous prime is 132411131959. The next prime is 132411132017. The reversal of 132411132000 is 231114231.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 693251905 + ... + 693252095.

It is an arithmetic number, because the mean of its divisors is an integer number (492972480).

Almost surely, 2132411132000 is an apocalyptic number.

132411132000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132411132000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (283952148480).

132411132000 is an abundant number, since it is smaller than the sum of its proper divisors (435493164960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132411132000 is a wasteful number, since it uses less digits than its factorization.

132411132000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 370 (or 339 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 132411132000 its reverse (231114231), we get a palindrome (132642246231).

The spelling of 132411132000 in words is "one hundred thirty-two billion, four hundred eleven million, one hundred thirty-two thousand".