Base | Representation |
---|---|
bin | 11110000110110101100011… |
… | …110110100010111001000101 |
3 | 122100211101111201121202102211 |
4 | 132012311203312202321011 |
5 | 114323411140313331321 |
6 | 1145340513045503421 |
7 | 36614252342505241 |
oct | 3606654366427105 |
9 | 570741451552384 |
10 | 132411222011461 |
11 | 39210313965748 |
12 | 12a26222411b71 |
13 | 58b642b375353 |
14 | 249aa47393421 |
15 | 10494be2650e1 |
hex | 786d63da2e45 |
132411222011461 has 2 divisors, whose sum is σ = 132411222011462. Its totient is φ = 132411222011460.
The previous prime is 132411222011407. The next prime is 132411222011501. The reversal of 132411222011461 is 164110222114231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 117921551370561 + 14489670640900 = 10859169^2 + 3806530^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132411222011461 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132411220011461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66205611005730 + 66205611005731.
It is an arithmetic number, because the mean of its divisors is an integer number (66205611005731).
Almost surely, 2132411222011461 is an apocalyptic number.
It is an amenable number.
132411222011461 is a deficient number, since it is larger than the sum of its proper divisors (1).
132411222011461 is an equidigital number, since it uses as much as digits as its factorization.
132411222011461 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4608, while the sum is 31.
Adding to 132411222011461 its reverse (164110222114231), we get a palindrome (296521444125692).
The spelling of 132411222011461 in words is "one hundred thirty-two trillion, four hundred eleven billion, two hundred twenty-two million, eleven thousand, four hundred sixty-one".
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