13241244031 has 2 divisors, whose sum is σ = 13241244032. Its totient is φ = 13241244030.

The previous prime is 13241243989. The next prime is 13241244043. The reversal of 13241244031 is 13044214231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13241244031 - 2²³ = 13232855423 is a prime.

It is a super-2 number, since 2×13241244031² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13241243987 and 13241244005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13241244931) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6620622015 + 6620622016.

It is an arithmetic number, because the mean of its divisors is an integer number (6620622016).

Almost surely, 2^13241244031 is an apocalyptic number.

13241244031 is a deficient number, since it is larger than the sum of its proper divisors (1).

13241244031 is an equidigital number, since it uses as much as digits as its factorization.

13241244031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 13241244031 its reverse (13044214231), we get a palindrome (26285458262).

The spelling of 13241244031 in words is "thirteen billion, two hundred forty-one million, two hundred forty-four thousand, thirty-one".