Base | Representation |
---|---|
bin | 111101101010001110… |
… | …0101101010010110111 |
3 | 110122210010000022101101 |
4 | 1323110130231102313 |
5 | 4132140302023411 |
6 | 140455124510531 |
7 | 12365216412622 |
oct | 1732434552267 |
9 | 418703008341 |
10 | 132413314231 |
11 | 51179955900 |
12 | 217b4b4b447 |
13 | c642b72713 |
14 | 65a1bd2db9 |
15 | 369eb698c1 |
hex | 1ed472d4b7 |
132413314231 has 12 divisors (see below), whose sum is σ = 145628190400. Its totient is φ = 120307112640.
The previous prime is 132413314147. The next prime is 132413314249.
132413314231 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 132413314231 - 221 = 132411217079 is a prime.
It is a super-2 number, since 2×1324133142312 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 132413314231.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132413311231) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 98226 + ... + 523903.
Almost surely, 2132413314231 is an apocalyptic number.
132413314231 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
132413314231 is a deficient number, since it is larger than the sum of its proper divisors (13214876169).
132413314231 is a wasteful number, since it uses less digits than its factorization.
132413314231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 623910 (or 623899 counting only the distinct ones).
The product of its digits is 5184, while the sum is 28.
It can be divided in two parts, 132413 and 314231, that added together give a palindrome (446644).
The spelling of 132413314231 in words is "one hundred thirty-two billion, four hundred thirteen million, three hundred fourteen thousand, two hundred thirty-one".
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