Base | Representation |
---|---|
bin | 11110000110110111100001… |
… | …011101100001100010101010 |
3 | 122100211120221121000020201201 |
4 | 132012313201131201202222 |
5 | 114323424444310202141 |
6 | 1145341502130034414 |
7 | 36614355512036323 |
oct | 3606674135414252 |
9 | 570746847006651 |
10 | 132413329381546 |
11 | 392111a5478014 |
12 | 12a26710118a0a |
13 | 58b66a5b439b5 |
14 | 249aba71db44a |
15 | 1049594286031 |
hex | 786de17618aa |
132413329381546 has 4 divisors (see below), whose sum is σ = 198619994072322. Its totient is φ = 66206664690772.
The previous prime is 132413329381517. The next prime is 132413329381547. The reversal of 132413329381546 is 645183923314231.
132413329381546 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 88321670957521 + 44091658424025 = 9397961^2 + 6640155^2 .
It is not an unprimeable number, because it can be changed into a prime (132413329381547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33103332345385 + ... + 33103332345388.
Almost surely, 2132413329381546 is an apocalyptic number.
132413329381546 is a deficient number, since it is larger than the sum of its proper divisors (66206664690776).
132413329381546 is an equidigital number, since it uses as much as digits as its factorization.
132413329381546 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66206664690775.
The product of its digits is 11197440, while the sum is 55.
The spelling of 132413329381546 in words is "one hundred thirty-two trillion, four hundred thirteen billion, three hundred twenty-nine million, three hundred eighty-one thousand, five hundred forty-six".
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