132413329381547 has 2 divisors, whose sum is σ = 132413329381548. Its totient is φ = 132413329381546.

The previous prime is 132413329381517. The next prime is 132413329381549. The reversal of 132413329381547 is 745183923314231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132413329381547 - 2²² = 132413325187243 is a prime.

It is a super-2 number, since 2×132413329381547² (a number of 29 digits) contains 22 as substring.

Together with 132413329381549, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 132413329381492 and 132413329381501.

It is not a weakly prime, because it can be changed into another prime (132413329381549) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66206664690773 + 66206664690774.

It is an arithmetic number, because the mean of its divisors is an integer number (66206664690774).

Almost surely, 2^{132413329381547} is an apocalyptic number.

132413329381547 is a deficient number, since it is larger than the sum of its proper divisors (1).

132413329381547 is an equidigital number, since it uses as much as digits as its factorization.

132413329381547 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 13063680, while the sum is 56.

The spelling of 132413329381547 in words is "one hundred thirty-two trillion, four hundred thirteen billion, three hundred twenty-nine million, three hundred eighty-one thousand, five hundred forty-seven".