Base | Representation |
---|---|
bin | 10011010001001100100… |
… | …010101111100100110101 |
3 | 11200120211011220221010202 |
4 | 103101030202233210311 |
5 | 133143311312301344 |
6 | 2452144313130245 |
7 | 164444164112621 |
oct | 23211442574465 |
9 | 4616734827122 |
10 | 1324134103349 |
11 | 4706201aa252 |
12 | 1947619b9985 |
13 | 97b33117b75 |
14 | 48134932181 |
15 | 2469caa594e |
hex | 1344c8af935 |
1324134103349 has 2 divisors, whose sum is σ = 1324134103350. Its totient is φ = 1324134103348.
The previous prime is 1324134103283. The next prime is 1324134103361. The reversal of 1324134103349 is 9433014314231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1307633416324 + 16500687025 = 1143518^2 + 128455^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1324134103349 is a prime.
It is a super-2 number, since 2×13241341033492 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1324134103399) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662067051674 + 662067051675.
It is an arithmetic number, because the mean of its divisors is an integer number (662067051675).
Almost surely, 21324134103349 is an apocalyptic number.
It is an amenable number.
1324134103349 is a deficient number, since it is larger than the sum of its proper divisors (1).
1324134103349 is an equidigital number, since it uses as much as digits as its factorization.
1324134103349 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 93312, while the sum is 38.
The spelling of 1324134103349 in words is "one trillion, three hundred twenty-four billion, one hundred thirty-four million, one hundred three thousand, three hundred forty-nine".
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