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13241404252523 is a prime number
BaseRepresentation
bin1100000010110000000100…
…1100100110000101101011
31201212212101020012011121002
43000230001030212011223
53213421343442040043
644055003411305215
72534442225033026
oct300540114460553
951785336164532
1013241404252523
114245714552707
12159a3335ab20b
13750874c670a5
1433ac5cdb21bd
1517e68ca27bb8
hexc0b0132616b

13241404252523 has 2 divisors, whose sum is σ = 13241404252524. Its totient is φ = 13241404252522.

The previous prime is 13241404252499. The next prime is 13241404252543. The reversal of 13241404252523 is 32525240414231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13241404252523 - 28 = 13241404252267 is a prime.

It is not a weakly prime, because it can be changed into another prime (13241404252543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6620702126261 + 6620702126262.

It is an arithmetic number, because the mean of its divisors is an integer number (6620702126262).

Almost surely, 213241404252523 is an apocalyptic number.

13241404252523 is a deficient number, since it is larger than the sum of its proper divisors (1).

13241404252523 is an equidigital number, since it uses as much as digits as its factorization.

13241404252523 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 230400, while the sum is 38.

Adding to 13241404252523 its reverse (32525240414231), we get a palindrome (45766644666754).

The spelling of 13241404252523 in words is "thirteen trillion, two hundred forty-one billion, four hundred four million, two hundred fifty-two thousand, five hundred twenty-three".