132414053441321 has 2 divisors, whose sum is σ = 132414053441322. Its totient is φ = 132414053441320.

The previous prime is 132414053441311. The next prime is 132414053441323. The reversal of 132414053441321 is 123144350414231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 131733832631296 + 680220810025 = 11477536^2 + 824755^2 .

It is a cyclic number.

It is not a de Polignac number, because 132414053441321 - 2¹⁴ = 132414053424937 is a prime.

It is a super-2 number, since 2×132414053441321² (a number of 29 digits) contains 22 as substring.

Together with 132414053441323, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (132414053441323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66207026720660 + 66207026720661.

It is an arithmetic number, because the mean of its divisors is an integer number (66207026720661).

Almost surely, 2^{132414053441321} is an apocalyptic number.

It is an amenable number.

132414053441321 is a deficient number, since it is larger than the sum of its proper divisors (1).

132414053441321 is an equidigital number, since it uses as much as digits as its factorization.

132414053441321 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 138240, while the sum is 38.

The spelling of 132414053441321 in words is "one hundred thirty-two trillion, four hundred fourteen billion, fifty-three million, four hundred forty-one thousand, three hundred twenty-one".