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13241953469981 is a prime number
BaseRepresentation
bin1100000010110010000111…
…1011101100011000011101
31201212220210111122022022102
43000230201323230120131
53213424010042014411
644055134111054445
72534461644225065
oct300544173543035
951786714568272
1013241953469981
114245976575935
12159a467511425
13750931992332
1433acb1cda3a5
1517e6c0d63d3b
hexc0b21eec61d

13241953469981 has 2 divisors, whose sum is σ = 13241953469982. Its totient is φ = 13241953469980.

The previous prime is 13241953469977. The next prime is 13241953470001. The reversal of 13241953469981 is 18996435914231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11770320024100 + 1471633445881 = 3430790^2 + 1213109^2 .

It is a cyclic number.

It is not a de Polignac number, because 13241953469981 - 22 = 13241953469977 is a prime.

It is a super-2 number, since 2×132419534699812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13241953409981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6620976734990 + 6620976734991.

It is an arithmetic number, because the mean of its divisors is an integer number (6620976734991).

Almost surely, 213241953469981 is an apocalyptic number.

It is an amenable number.

13241953469981 is a deficient number, since it is larger than the sum of its proper divisors (1).

13241953469981 is an equidigital number, since it uses as much as digits as its factorization.

13241953469981 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 50388480, while the sum is 65.

The spelling of 13241953469981 in words is "thirteen trillion, two hundred forty-one billion, nine hundred fifty-three million, four hundred sixty-nine thousand, nine hundred eighty-one".