Base | Representation |
---|---|
bin | 1100000010110010010011… |
… | …0001110110001011110101 |
3 | 1201212220220211111021111021 |
4 | 3000230210301312023311 |
5 | 3213424104303022331 |
6 | 44055142534341141 |
7 | 2534463064133005 |
oct | 300544461661365 |
9 | 51786824437437 |
10 | 13242001220341 |
11 | 42459a051a443 |
12 | 159a47b4ba7b1 |
13 | 75093b84079a |
14 | 33acb83aa005 |
15 | 17e6c5147211 |
hex | c0b24c762f5 |
13242001220341 has 2 divisors, whose sum is σ = 13242001220342. Its totient is φ = 13242001220340.
The previous prime is 13242001220323. The next prime is 13242001220417. The reversal of 13242001220341 is 14302210024231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12316913126116 + 925088094225 = 3509546^2 + 961815^2 .
It is a cyclic number.
It is not a de Polignac number, because 13242001220341 - 27 = 13242001220213 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13242001220741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6621000610170 + 6621000610171.
It is an arithmetic number, because the mean of its divisors is an integer number (6621000610171).
Almost surely, 213242001220341 is an apocalyptic number.
It is an amenable number.
13242001220341 is a deficient number, since it is larger than the sum of its proper divisors (1).
13242001220341 is an equidigital number, since it uses as much as digits as its factorization.
13242001220341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 13242001220341 its reverse (14302210024231), we get a palindrome (27544211244572).
The spelling of 13242001220341 in words is "thirteen trillion, two hundred forty-two billion, one million, two hundred twenty thousand, three hundred forty-one".
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