Base | Representation |
---|---|
bin | 111101101010011011… |
… | …0101110010001111010 |
3 | 110122210120211210100210 |
4 | 1323110312232101322 |
5 | 4132144023242020 |
6 | 140455531011550 |
7 | 12365331365433 |
oct | 1732466562172 |
9 | 418716753323 |
10 | 132420134010 |
11 | 5118279368a |
12 | 217b7299bb6 |
13 | c6443bc8a8 |
14 | 65a2a8a48a |
15 | 36a05653e0 |
hex | 1ed4dae47a |
132420134010 has 64 divisors (see below), whose sum is σ = 322985988864. Its totient is φ = 34738905600.
The previous prime is 132420133997. The next prime is 132420134027. The reversal of 132420134010 is 10431024231.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 914502 + ... + 1049358.
It is an arithmetic number, because the mean of its divisors is an integer number (5046656076).
Almost surely, 2132420134010 is an apocalyptic number.
132420134010 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 132420134010, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (161492994432).
132420134010 is an abundant number, since it is smaller than the sum of its proper divisors (190565854854).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132420134010 is a wasteful number, since it uses less digits than its factorization.
132420134010 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 135399.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 132420134010 its reverse (10431024231), we get a palindrome (142851158241).
The spelling of 132420134010 in words is "one hundred thirty-two billion, four hundred twenty million, one hundred thirty-four thousand, ten".
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