Base | Representation |
---|---|
bin | 11000101010100100… |
… | …11010010100111011 |
3 | 1021011212020211102210 |
4 | 30111102122110323 |
5 | 204104431043401 |
6 | 10025555030203 |
7 | 646102365222 |
oct | 142522322473 |
9 | 37155224383 |
10 | 13242049851 |
11 | 5685879058 |
12 | 269689b363 |
13 | 133058c874 |
14 | 8d8975cb9 |
15 | 5278154d6 |
hex | 31549a53b |
13242049851 has 8 divisors (see below), whose sum is σ = 17659823680. Its totient is φ = 8826154632.
The previous prime is 13242049837. The next prime is 13242049859. The reversal of 13242049851 is 15894024231.
13242049851 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13242049851 - 26 = 13242049787 is a prime.
It is a super-4 number, since 4×132420498514 (a number of 42 digits) contains 4444 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13242049859) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 453121 + ... + 481458.
It is an arithmetic number, because the mean of its divisors is an integer number (2207477960).
Almost surely, 213242049851 is an apocalyptic number.
13242049851 is a deficient number, since it is larger than the sum of its proper divisors (4417773829).
13242049851 is an equidigital number, since it uses as much as digits as its factorization.
13242049851 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 939305.
The product of its (nonzero) digits is 69120, while the sum is 39.
The spelling of 13242049851 in words is "thirteen billion, two hundred forty-two million, forty-nine thousand, eight hundred fifty-one".
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