Base | Representation |
---|---|
bin | 11000101010100101… |
… | …00110111010011001 |
3 | 1021011212100110011001 |
4 | 30111102212322121 |
5 | 204104434221101 |
6 | 10030000105001 |
7 | 646103001424 |
oct | 142522467231 |
9 | 37155313131 |
10 | 13242101401 |
11 | 5685903861 |
12 | 2696905161 |
13 | 13305aa179 |
14 | 8d898a9bb |
15 | 527825901 |
hex | 3154a6e99 |
13242101401 has 2 divisors, whose sum is σ = 13242101402. Its totient is φ = 13242101400.
The previous prime is 13242101387. The next prime is 13242101419. The reversal of 13242101401 is 10410124231.
13242101401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8258447376 + 4983654025 = 90876^2 + 70595^2 .
It is a cyclic number.
It is not a de Polignac number, because 13242101401 - 219 = 13241577113 is a prime.
It is not a weakly prime, because it can be changed into another prime (13242101501) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6621050700 + 6621050701.
It is an arithmetic number, because the mean of its divisors is an integer number (6621050701).
Almost surely, 213242101401 is an apocalyptic number.
It is an amenable number.
13242101401 is a deficient number, since it is larger than the sum of its proper divisors (1).
13242101401 is an equidigital number, since it uses as much as digits as its factorization.
13242101401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 13242101401 its reverse (10410124231), we get a palindrome (23652225632).
The spelling of 13242101401 in words is "thirteen billion, two hundred forty-two million, one hundred one thousand, four hundred one".
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