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13242131347 is a prime number
BaseRepresentation
bin11000101010100101…
…01110001110010011
31021011212101222020011
430111102232032103
5204104441200342
610030000455351
7646103154634
oct142522561623
937155358204
1013242131347
115685924305
12269691a557
1313305ba9a3
148d899788b
1552782e717
hex3154ae393

13242131347 has 2 divisors, whose sum is σ = 13242131348. Its totient is φ = 13242131346.

The previous prime is 13242131327. The next prime is 13242131401. The reversal of 13242131347 is 74313124231.

13242131347 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (74313124231) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13242131347 is a prime.

It is a super-2 number, since 2×132421313472 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13242131327) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6621065673 + 6621065674.

It is an arithmetic number, because the mean of its divisors is an integer number (6621065674).

Almost surely, 213242131347 is an apocalyptic number.

13242131347 is a deficient number, since it is larger than the sum of its proper divisors (1).

13242131347 is an equidigital number, since it uses as much as digits as its factorization.

13242131347 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12096, while the sum is 31.

Adding to 13242131347 its reverse (74313124231), we get a palindrome (87555255578).

The spelling of 13242131347 in words is "thirteen billion, two hundred forty-two million, one hundred thirty-one thousand, three hundred forty-seven".