Base | Representation |
---|---|
bin | 11110000110111111000100… |
… | …100000110110110010011010 |
3 | 122100212100212101121202111211 |
4 | 132012333010200312302122 |
5 | 114324043044003302310 |
6 | 1145345322232413334 |
7 | 36615063400141156 |
oct | 3606770440666232 |
9 | 570770771552454 |
10 | 132421433650330 |
11 | 39214684092110 |
12 | 12a281b224724a |
13 | 58b7397b63606 |
14 | 249b335688066 |
15 | 10498ba9cac8a |
hex | 786fc4836c9a |
132421433650330 has 64 divisors (see below), whose sum is σ = 272016414604800. Its totient is φ = 45970400734720.
The previous prime is 132421433650327. The next prime is 132421433650349. The reversal of 132421433650330 is 33056334124231.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 232926322 + ... + 233494141.
It is an arithmetic number, because the mean of its divisors is an integer number (4250256478200).
Almost surely, 2132421433650330 is an apocalyptic number.
132421433650330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132421433650330 is an abundant number, since it is smaller than the sum of its proper divisors (139594980954470).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132421433650330 is a wasteful number, since it uses less digits than its factorization.
132421433650330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 466420599.
The product of its (nonzero) digits is 466560, while the sum is 40.
Adding to 132421433650330 its reverse (33056334124231), we get a palindrome (165477767774561).
The spelling of 132421433650330 in words is "one hundred thirty-two trillion, four hundred twenty-one billion, four hundred thirty-three million, six hundred fifty thousand, three hundred thirty".
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