Base | Representation |
---|---|
bin | 1100000010110011000010… |
… | …1000001111111110001001 |
3 | 1201212221102200120220121012 |
4 | 3000230300220033332021 |
5 | 3213430011201443423 |
6 | 44055214355453305 |
7 | 2534501030035154 |
oct | 300546050177611 |
9 | 51787380526535 |
10 | 13242200031113 |
11 | 4245a9276a969 |
12 | 159a515bb7235 |
13 | 750970a9c6b1 |
14 | 33acd695cc9b |
15 | 17e6d7819078 |
hex | c0b30a0ff89 |
13242200031113 has 2 divisors, whose sum is σ = 13242200031114. Its totient is φ = 13242200031112.
The previous prime is 13242200031043. The next prime is 13242200031139. The reversal of 13242200031113 is 31113000224231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12743950397689 + 498249633424 = 3569867^2 + 705868^2 .
It is an emirp because it is prime and its reverse (31113000224231) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13242200031113 is a prime.
It is not a weakly prime, because it can be changed into another prime (13242200031173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6621100015556 + 6621100015557.
It is an arithmetic number, because the mean of its divisors is an integer number (6621100015557).
Almost surely, 213242200031113 is an apocalyptic number.
It is an amenable number.
13242200031113 is a deficient number, since it is larger than the sum of its proper divisors (1).
13242200031113 is an equidigital number, since it uses as much as digits as its factorization.
13242200031113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 13242200031113 its reverse (31113000224231), we get a palindrome (44355200255344).
The spelling of 13242200031113 in words is "thirteen trillion, two hundred forty-two billion, two hundred million, thirty-one thousand, one hundred thirteen".
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