Base | Representation |
---|---|
bin | 11110000110111111101101… |
… | …001110010010110101101111 |
3 | 122100212102121222210202101220 |
4 | 132012333231032102311233 |
5 | 114324100443330302401 |
6 | 1145345514111434423 |
7 | 36615116332426653 |
oct | 3606775516226557 |
9 | 570772558722356 |
10 | 132422116650351 |
11 | 392149a4680140 |
12 | 12a28362b25a13 |
13 | 58b74764ccc38 |
14 | 249b39c278a63 |
15 | 104990a941336 |
hex | 786fed392d6f |
132422116650351 has 16 divisors (see below), whose sum is σ = 193073687130240. Its totient is φ = 80064286908320.
The previous prime is 132422116650319. The next prime is 132422116650379. The reversal of 132422116650351 is 153056611224231.
It is not a de Polignac number, because 132422116650351 - 25 = 132422116650319 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132422116650151) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4788520080 + ... + 4788547733.
It is an arithmetic number, because the mean of its divisors is an integer number (12067105445640).
Almost surely, 2132422116650351 is an apocalyptic number.
132422116650351 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
132422116650351 is a deficient number, since it is larger than the sum of its proper divisors (60651570479889).
132422116650351 is a wasteful number, since it uses less digits than its factorization.
132422116650351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9577068246.
The product of its (nonzero) digits is 259200, while the sum is 42.
Adding to 132422116650351 its reverse (153056611224231), we get a palindrome (285478727874582).
The spelling of 132422116650351 in words is "one hundred thirty-two trillion, four hundred twenty-two billion, one hundred sixteen million, six hundred fifty thousand, three hundred fifty-one".
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