Base | Representation |
---|---|
bin | 11110000111000010111001… |
… | …100110011000000111101111 |
3 | 122100212202110221211011010112 |
4 | 132013002321212120013233 |
5 | 114324130004122444003 |
6 | 1145351242240130235 |
7 | 36615300316335242 |
oct | 3607027146300757 |
9 | 570782427734115 |
10 | 132425545515503 |
11 | 392163a4131299 |
12 | 12a28b5b30697b |
13 | 58b78a19c1326 |
14 | 249b6057db259 |
15 | 1049a5b99b3d8 |
hex | 7870b99981ef |
132425545515503 has 4 divisors (see below), whose sum is σ = 132427026063600. Its totient is φ = 132424064967408.
The previous prime is 132425545515463. The next prime is 132425545515509. The reversal of 132425545515503 is 305515545524231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132425545515503 - 218 = 132425545253359 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132425545515509) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 740139875 + ... + 740318772.
It is an arithmetic number, because the mean of its divisors is an integer number (33106756515900).
Almost surely, 2132425545515503 is an apocalyptic number.
132425545515503 is a deficient number, since it is larger than the sum of its proper divisors (1480548097).
132425545515503 is an equidigital number, since it uses as much as digits as its factorization.
132425545515503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1480548096.
The product of its (nonzero) digits is 9000000, while the sum is 50.
The spelling of 132425545515503 in words is "one hundred thirty-two trillion, four hundred twenty-five billion, five hundred forty-five million, five hundred fifteen thousand, five hundred three".
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