Base | Representation |
---|---|
bin | 1100000010110100101011… |
… | …1011010011011111101111 |
3 | 1201212222120102210100001021 |
4 | 3000231022323103133233 |
5 | 3213431412123441103 |
6 | 44055330240155011 |
7 | 2534514665144524 |
oct | 300551273233757 |
9 | 51788512710037 |
10 | 13242641233903 |
11 | 4246199818074 |
12 | 159a619908a67 |
13 | 750a11309133 |
14 | 33ad393ab14b |
15 | 17e71141abbd |
hex | c0b4aed37ef |
13242641233903 has 2 divisors, whose sum is σ = 13242641233904. Its totient is φ = 13242641233902.
The previous prime is 13242641233891. The next prime is 13242641233981. The reversal of 13242641233903 is 30933214624231.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13242641233903 is a prime.
It is a super-2 number, since 2×132426412339032 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13242641233903.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13242641233993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6621320616951 + 6621320616952.
It is an arithmetic number, because the mean of its divisors is an integer number (6621320616952).
Almost surely, 213242641233903 is an apocalyptic number.
13242641233903 is a deficient number, since it is larger than the sum of its proper divisors (1).
13242641233903 is an equidigital number, since it uses as much as digits as its factorization.
13242641233903 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 559872, while the sum is 43.
The spelling of 13242641233903 in words is "thirteen trillion, two hundred forty-two billion, six hundred forty-one million, two hundred thirty-three thousand, nine hundred three".
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