Base | Representation |
---|---|
bin | 1100000010110101001001… |
… | …0011110111000000101101 |
3 | 1201212222220001212221221112 |
4 | 3000231102103313000231 |
5 | 3213432140332030331 |
6 | 44055350423241405 |
7 | 2534521031115323 |
oct | 300552223670055 |
9 | 51788801787845 |
10 | 13242765111341 |
11 | 4246252738017 |
12 | 159a6532a9265 |
13 | 750a30b8cbac |
14 | 33ad4ba15d13 |
15 | 17e71c23a32b |
hex | c0b524f702d |
13242765111341 has 8 divisors (see below), whose sum is σ = 13939786428480. Its totient is φ = 12545747162208.
The previous prime is 13242765111293. The next prime is 13242765111347. The reversal of 13242765111341 is 14311156724231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13242765111341 - 214 = 13242765094957 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13242765111347) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13444040 + ... + 14395406.
It is an arithmetic number, because the mean of its divisors is an integer number (1742473303560).
Almost surely, 213242765111341 is an apocalyptic number.
It is an amenable number.
13242765111341 is a deficient number, since it is larger than the sum of its proper divisors (697021317139).
13242765111341 is an equidigital number, since it uses as much as digits as its factorization.
13242765111341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1684003.
The product of its digits is 120960, while the sum is 41.
The spelling of 13242765111341 in words is "thirteen trillion, two hundred forty-two billion, seven hundred sixty-five million, one hundred eleven thousand, three hundred forty-one".
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