Base | Representation |
---|---|
bin | 11000101010101100… |
… | …01001111001001011 |
3 | 1021011221002200110220 |
4 | 30111112021321023 |
5 | 204110203443430 |
6 | 10030032041123 |
7 | 646113623106 |
oct | 142526117113 |
9 | 37157080426 |
10 | 13243031115 |
11 | 5686389316 |
12 | 26970931a3 |
13 | 13308443b2 |
14 | 8d8b4d73d |
15 | 52795b110 |
hex | 315589e4b |
13243031115 has 16 divisors (see below), whose sum is σ = 21487286016. Its totient is φ = 6963471200.
The previous prime is 13243031089. The next prime is 13243031159. The reversal of 13243031115 is 51113034231.
13243031115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13243031115 - 27 = 13243030987 is a prime.
It is a super-2 number, since 2×132430311152 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6216321 + ... + 6218450.
It is an arithmetic number, because the mean of its divisors is an integer number (1342955376).
Almost surely, 213243031115 is an apocalyptic number.
13243031115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13243031115 is a deficient number, since it is larger than the sum of its proper divisors (8244254901).
13243031115 is a wasteful number, since it uses less digits than its factorization.
13243031115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12434850.
The product of its (nonzero) digits is 1080, while the sum is 24.
Adding to 13243031115 its reverse (51113034231), we get a palindrome (64356065346).
The spelling of 13243031115 in words is "thirteen billion, two hundred forty-three million, thirty-one thousand, one hundred fifteen".
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