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132430433 = 2933591259
BaseRepresentation
bin1111110010010…
…11101001100001
3100020012011101212
413321023221201
5232400233213
621050235505
73165432362
oct771135141
9306164355
10132430433
1168831a43
1238425b95
1321589b05
1413833b69
15b95d9a8
hex7e4ba61

132430433 has 8 divisors (see below), whose sum is σ = 133358400. Its totient is φ = 131506288.

The previous prime is 132430429. The next prime is 132430439. The reversal of 132430433 is 334034231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 132430433 - 22 = 132430429 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132430399 and 132430408.

It is not an unprimeable number, because it can be changed into a prime (132430439) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 104558 + ... + 105816.

It is an arithmetic number, because the mean of its divisors is an integer number (16669800).

Almost surely, 2132430433 is an apocalyptic number.

It is an amenable number.

132430433 is a deficient number, since it is larger than the sum of its proper divisors (927967).

132430433 is a wasteful number, since it uses less digits than its factorization.

132430433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1911.

The product of its (nonzero) digits is 2592, while the sum is 23.

The square root of 132430433 is about 11507.8422390994. The cubic root of 132430433 is about 509.7171736984.

Adding to 132430433 its reverse (334034231), we get a palindrome (466464664).

The spelling of 132430433 in words is "one hundred thirty-two million, four hundred thirty thousand, four hundred thirty-three".

Divisors: 1 293 359 1259 105187 368887 451981 132430433