Base | Representation |
---|---|
bin | 11110000111001001111010… |
… | …010100000001000011010111 |
3 | 122100220110220121101010222121 |
4 | 132013021322110001003113 |
5 | 114324240413330004112 |
6 | 1145354525242440411 |
7 | 36615655010532454 |
oct | 3607117224010327 |
9 | 570813817333877 |
10 | 132433073672407 |
11 | 39219607623a72 |
12 | 12a2a500503107 |
13 | 58b850155a441 |
14 | 249bb1b55c82b |
15 | 1049d4c841407 |
hex | 78727a5010d7 |
132433073672407 has 2 divisors, whose sum is σ = 132433073672408. Its totient is φ = 132433073672406.
The previous prime is 132433073672381. The next prime is 132433073672423. The reversal of 132433073672407 is 704276370334231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132433073672407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132433073675407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66216536836203 + 66216536836204.
It is an arithmetic number, because the mean of its divisors is an integer number (66216536836204).
Almost surely, 2132433073672407 is an apocalyptic number.
132433073672407 is a deficient number, since it is larger than the sum of its proper divisors (1).
132433073672407 is an equidigital number, since it uses as much as digits as its factorization.
132433073672407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10668672, while the sum is 52.
The spelling of 132433073672407 in words is "one hundred thirty-two trillion, four hundred thirty-three billion, seventy-three million, six hundred seventy-two thousand, four hundred seven".
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