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132440224141 is a prime number
BaseRepresentation
bin111101101011000001…
…1010111000110001101
3110122211222122110211201
41323112003113012031
54132214144133031
6140501525345501
712365664221311
oct1732603270615
9418758573751
10132440224141
11511930656a5
1221801b68291
13c648605044
1465a55d9b41
1536a21d2d61
hex1ed60d718d

132440224141 has 2 divisors, whose sum is σ = 132440224142. Its totient is φ = 132440224140.

The previous prime is 132440224117. The next prime is 132440224171. The reversal of 132440224141 is 141422044231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 127045909225 + 5394314916 = 356435^2 + 73446^2 .

It is a cyclic number.

It is not a de Polignac number, because 132440224141 - 229 = 131903353229 is a prime.

It is a super-4 number, since 4×1324402241414 (a number of 46 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132440224171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66220112070 + 66220112071.

It is an arithmetic number, because the mean of its divisors is an integer number (66220112071).

Almost surely, 2132440224141 is an apocalyptic number.

It is an amenable number.

132440224141 is a deficient number, since it is larger than the sum of its proper divisors (1).

132440224141 is an equidigital number, since it uses as much as digits as its factorization.

132440224141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6144, while the sum is 28.

Adding to 132440224141 its reverse (141422044231), we get a palindrome (273862268372).

The spelling of 132440224141 in words is "one hundred thirty-two billion, four hundred forty million, two hundred twenty-four thousand, one hundred forty-one".