132440500111300 has 18 divisors (see below), whose sum is σ = 287395885241738. Its totient is φ = 52976200044480.

The previous prime is 132440500111229. The next prime is 132440500111307. The reversal of 132440500111300 is 3111005044231.

It can be written as a sum of positive squares in 3 ways, for example, as 33352172717956 + 99088327393344 = 5775134^2 + 9954312^2 .

It is a Harshad number since it is a multiple of its sum of digits (25).

It is not an unprimeable number, because it can be changed into a prime (132440500111307) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 662202500457 + ... + 662202500656.

Almost surely, 2^{132440500111300} is an apocalyptic number.

132440500111300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

132440500111300 is an abundant number, since it is smaller than the sum of its proper divisors (154955385130438).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132440500111300 is a wasteful number, since it uses less digits than its factorization.

132440500111300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1324405001127 (or 1324405001120 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 132440500111300 its reverse (3111005044231), we get a palindrome (135551505155531).

The spelling of 132440500111300 in words is "one hundred thirty-two trillion, four hundred forty billion, five hundred million, one hundred eleven thousand, three hundred".