Base | Representation |
---|---|
bin | 10011010001011101000… |
… | …011011011000101000111 |
3 | 11200121112111011002210122 |
4 | 103101131003123011013 |
5 | 133144343220334412 |
6 | 2452232010212155 |
7 | 164454066436442 |
oct | 23213503330507 |
9 | 4617474132718 |
10 | 1324411105607 |
11 | 4707525a6137 |
12 | 19481a72405b |
13 | 97b78622c25 |
14 | 4815d63a659 |
15 | 246b7070572 |
hex | 1345d0db147 |
1324411105607 has 2 divisors, whose sum is σ = 1324411105608. Its totient is φ = 1324411105606.
The previous prime is 1324411105517. The next prime is 1324411105643. The reversal of 1324411105607 is 7065011144231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1324411105607 - 218 = 1324410843463 is a prime.
It is a super-2 number, since 2×13244111056072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1324411105907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662205552803 + 662205552804.
It is an arithmetic number, because the mean of its divisors is an integer number (662205552804).
Almost surely, 21324411105607 is an apocalyptic number.
1324411105607 is a deficient number, since it is larger than the sum of its proper divisors (1).
1324411105607 is an equidigital number, since it uses as much as digits as its factorization.
1324411105607 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 35.
Adding to 1324411105607 its reverse (7065011144231), we get a palindrome (8389422249838).
The spelling of 1324411105607 in words is "one trillion, three hundred twenty-four billion, four hundred eleven million, one hundred five thousand, six hundred seven".
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