Base | Representation |
---|---|
bin | 111101101011000111… |
… | …0101101101010010011 |
3 | 110122212012020200011011 |
4 | 1323112032231222103 |
5 | 4132220424401042 |
6 | 140502113231351 |
7 | 12366031424566 |
oct | 1732616555223 |
9 | 418765220134 |
10 | 132443200147 |
11 | 51194808605 |
12 | 21802b62557 |
13 | c6491077ab |
14 | 65a5b724dd |
15 | 36a25bea17 |
hex | 1ed63ada93 |
132443200147 has 2 divisors, whose sum is σ = 132443200148. Its totient is φ = 132443200146.
The previous prime is 132443200139. The next prime is 132443200217. The reversal of 132443200147 is 741002344231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132443200147 - 23 = 132443200139 is a prime.
It is not a weakly prime, because it can be changed into another prime (132443200847) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66221600073 + 66221600074.
It is an arithmetic number, because the mean of its divisors is an integer number (66221600074).
Almost surely, 2132443200147 is an apocalyptic number.
132443200147 is a deficient number, since it is larger than the sum of its proper divisors (1).
132443200147 is an equidigital number, since it uses as much as digits as its factorization.
132443200147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 31.
Adding to 132443200147 its reverse (741002344231), we get a palindrome (873445544378).
The spelling of 132443200147 in words is "one hundred thirty-two billion, four hundred forty-three million, two hundred thousand, one hundred forty-seven".
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