Base | Representation |
---|---|
bin | 1100000010111011110010… |
… | …1101011100001100101111 |
3 | 1201220011111110211222012021 |
4 | 3000232330231130030233 |
5 | 3213444314322432114 |
6 | 44100243512051011 |
7 | 2534613205125613 |
oct | 300567455341457 |
9 | 51804443758167 |
10 | 13244550202159 |
11 | 4246a89339191 |
12 | 159aa71093a67 |
13 | 750c5695ca53 |
14 | 33b07ab2b343 |
15 | 17e7c3ceb024 |
hex | c0bbcb5c32f |
13244550202159 has 2 divisors, whose sum is σ = 13244550202160. Its totient is φ = 13244550202158.
The previous prime is 13244550202049. The next prime is 13244550202187. The reversal of 13244550202159 is 95120205544231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13244550202159 - 213 = 13244550193967 is a prime.
It is a super-2 number, since 2×132445502021592 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13244550202189) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6622275101079 + 6622275101080.
It is an arithmetic number, because the mean of its divisors is an integer number (6622275101080).
Almost surely, 213244550202159 is an apocalyptic number.
13244550202159 is a deficient number, since it is larger than the sum of its proper divisors (1).
13244550202159 is an equidigital number, since it uses as much as digits as its factorization.
13244550202159 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432000, while the sum is 43.
The spelling of 13244550202159 in words is "thirteen trillion, two hundred forty-four billion, five hundred fifty million, two hundred two thousand, one hundred fifty-nine".
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