Base | Representation |
---|---|
bin | 1100000010111100011100… |
… | …0100100101001110001111 |
3 | 1201220011221120221212200201 |
4 | 3000233013010211032033 |
5 | 3214000143323244331 |
6 | 44100313042034331 |
7 | 2534620415542321 |
oct | 300570704451617 |
9 | 51804846855621 |
10 | 13244724040591 |
11 | 424706848260a |
12 | 159aabb3489a7 |
13 | 750c83987224 |
14 | 33b095c5d611 |
15 | 17e7d41d8a61 |
hex | c0bc712538f |
13244724040591 has 2 divisors, whose sum is σ = 13244724040592. Its totient is φ = 13244724040590.
The previous prime is 13244724040501. The next prime is 13244724040619. The reversal of 13244724040591 is 19504042744231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13244724040591 - 213 = 13244724032399 is a prime.
It is a super-2 number, since 2×132447240405912 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13244724040501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6622362020295 + 6622362020296.
It is an arithmetic number, because the mean of its divisors is an integer number (6622362020296).
Almost surely, 213244724040591 is an apocalyptic number.
13244724040591 is a deficient number, since it is larger than the sum of its proper divisors (1).
13244724040591 is an equidigital number, since it uses as much as digits as its factorization.
13244724040591 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 967680, while the sum is 46.
The spelling of 13244724040591 in words is "thirteen trillion, two hundred forty-four billion, seven hundred twenty-four million, forty thousand, five hundred ninety-one".
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