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132457181457313 is a prime number
BaseRepresentation
bin11110000111100000010111…
…001111111010101110100001
3122100222210010201102111210001
4132013200113033322232201
5114330134301423113223
61145413553352140001
736620500302400606
oct3607402717725641
9570883121374701
10132457181457313
1139228858865649
1212a3310a097601
1358ba873c9481b
14249cd672146ad
15104a7ae0239ad
hex7878173faba1

132457181457313 has 2 divisors, whose sum is σ = 132457181457314. Its totient is φ = 132457181457312.

The previous prime is 132457181457311. The next prime is 132457181457317. The reversal of 132457181457313 is 313754181754231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 97908096101904 + 34549085355409 = 9894852^2 + 5877847^2 .

It is a cyclic number.

It is not a de Polignac number, because 132457181457313 - 21 = 132457181457311 is a prime.

Together with 132457181457311, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (132457181457311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66228590728656 + 66228590728657.

It is an arithmetic number, because the mean of its divisors is an integer number (66228590728657).

Almost surely, 2132457181457313 is an apocalyptic number.

It is an amenable number.

132457181457313 is a deficient number, since it is larger than the sum of its proper divisors (1).

132457181457313 is an equidigital number, since it uses as much as digits as its factorization.

132457181457313 is an evil number, because the sum of its binary digits is even.

The product of its digits is 8467200, while the sum is 55.

The spelling of 132457181457313 in words is "one hundred thirty-two trillion, four hundred fifty-seven billion, one hundred eighty-one million, four hundred fifty-seven thousand, three hundred thirteen".