Base | Representation |
---|---|
bin | 1100000011000101110010… |
… | …0011100011011100110111 |
3 | 1201220102102101001122012022 |
4 | 3000301130203203130313 |
5 | 3214020312340334413 |
6 | 44101405551343355 |
7 | 2535036520544252 |
oct | 300613443433467 |
9 | 51812371048168 |
10 | 13247231964983 |
11 | 42481350a92a5 |
12 | 159b49b221b5b |
13 | 75129342c563 |
14 | 33b252d74099 |
15 | 17e8ce47c608 |
hex | c0c5c8e3737 |
13247231964983 has 2 divisors, whose sum is σ = 13247231964984. Its totient is φ = 13247231964982.
The previous prime is 13247231964959. The next prime is 13247231965003. The reversal of 13247231964983 is 38946913274231.
13247231964983 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13247231964983 - 28 = 13247231964727 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13247231960983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6623615982491 + 6623615982492.
It is an arithmetic number, because the mean of its divisors is an integer number (6623615982492).
Almost surely, 213247231964983 is an apocalyptic number.
13247231964983 is a deficient number, since it is larger than the sum of its proper divisors (1).
13247231964983 is an equidigital number, since it uses as much as digits as its factorization.
13247231964983 is an evil number, because the sum of its binary digits is even.
The product of its digits is 47029248, while the sum is 62.
The spelling of 13247231964983 in words is "thirteen trillion, two hundred forty-seven billion, two hundred thirty-one million, nine hundred sixty-four thousand, nine hundred eighty-three".
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