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13250040222235 = 56143442754827
BaseRepresentation
bin1100000011010000001111…
…1100001101001000011011
31201220200200002021212221011
43000310003330031020123
53214042040244102420
644102552350154351
72535166230413215
oct300640374151033
951820602255834
1013250040222235
114249346306563
12159bb437b29b7
1375162018b03b
1433b43bd075b5
1517e9e5c9895a
hexc0d03f0d21b

13250040222235 has 8 divisors (see below), whose sum is σ = 16160704796016. Its totient is φ = 10426261158240.

The previous prime is 13250040222203. The next prime is 13250040222343. The reversal of 13250040222235 is 53222204005231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13250040222235 - 25 = 13250040222203 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13250040222197 and 13250040222206.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21721377109 + ... + 21721377718.

It is an arithmetic number, because the mean of its divisors is an integer number (2020088099502).

Almost surely, 213250040222235 is an apocalyptic number.

13250040222235 is a deficient number, since it is larger than the sum of its proper divisors (2910664573781).

13250040222235 is an equidigital number, since it uses as much as digits as its factorization.

13250040222235 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43442754893.

The product of its (nonzero) digits is 28800, while the sum is 31.

Adding to 13250040222235 its reverse (53222204005231), we get a palindrome (66472244227466).

The spelling of 13250040222235 in words is "thirteen trillion, two hundred fifty billion, forty million, two hundred twenty-two thousand, two hundred thirty-five".

Divisors: 1 5 61 305 43442754827 217213774135 2650008044447 13250040222235