Base | Representation |
---|---|
bin | 1100000011010000001111… |
… | …1100001101001000011011 |
3 | 1201220200200002021212221011 |
4 | 3000310003330031020123 |
5 | 3214042040244102420 |
6 | 44102552350154351 |
7 | 2535166230413215 |
oct | 300640374151033 |
9 | 51820602255834 |
10 | 13250040222235 |
11 | 4249346306563 |
12 | 159bb437b29b7 |
13 | 75162018b03b |
14 | 33b43bd075b5 |
15 | 17e9e5c9895a |
hex | c0d03f0d21b |
13250040222235 has 8 divisors (see below), whose sum is σ = 16160704796016. Its totient is φ = 10426261158240.
The previous prime is 13250040222203. The next prime is 13250040222343. The reversal of 13250040222235 is 53222204005231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13250040222235 - 25 = 13250040222203 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13250040222197 and 13250040222206.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21721377109 + ... + 21721377718.
It is an arithmetic number, because the mean of its divisors is an integer number (2020088099502).
Almost surely, 213250040222235 is an apocalyptic number.
13250040222235 is a deficient number, since it is larger than the sum of its proper divisors (2910664573781).
13250040222235 is an equidigital number, since it uses as much as digits as its factorization.
13250040222235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 43442754893.
The product of its (nonzero) digits is 28800, while the sum is 31.
Adding to 13250040222235 its reverse (53222204005231), we get a palindrome (66472244227466).
The spelling of 13250040222235 in words is "thirteen trillion, two hundred fifty billion, forty million, two hundred twenty-two thousand, two hundred thirty-five".
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