Base | Representation |
---|---|
bin | 10011010010000001000… |
… | …001001100111011101111 |
3 | 11200200002112112212121211 |
4 | 103102001001030323233 |
5 | 133202112203100101 |
6 | 2452411523135251 |
7 | 164505044306113 |
oct | 23220101147357 |
9 | 4620075485554 |
10 | 1325014503151 |
11 | 470a32164699 |
12 | 194968814527 |
13 | 97c4363b0b1 |
14 | 481b9829743 |
15 | 2470000ec51 |
hex | 1348104ceef |
1325014503151 has 4 divisors (see below), whose sum is σ = 1394752108600. Its totient is φ = 1255276897704.
The previous prime is 1325014503061. The next prime is 1325014503191. The reversal of 1325014503151 is 1513054105231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1325014503151 - 235 = 1290654764783 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1325014503191) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34868802696 + ... + 34868802733.
It is an arithmetic number, because the mean of its divisors is an integer number (348688027150).
Almost surely, 21325014503151 is an apocalyptic number.
1325014503151 is a deficient number, since it is larger than the sum of its proper divisors (69737605449).
1325014503151 is an equidigital number, since it uses as much as digits as its factorization.
1325014503151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69737605448.
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 1325014503151 its reverse (1513054105231), we get a palindrome (2838068608382).
The spelling of 1325014503151 in words is "one trillion, three hundred twenty-five billion, fourteen million, five hundred three thousand, one hundred fifty-one".
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