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132503255501231 = 1091215626197259
BaseRepresentation
bin11110001000001011010001…
…011110011100100110101111
3122101011012001200212110010002
4132020023101132130212233
5114331413131402014411
61145451053310534515
736624021123325346
oct3610132136344657
9571135050773102
10132503255501231
113924635141779a
1212a4002820743b
1358c20075691c4
1424a1298386b5d
15104baa8dbc33b
hex7882d179c9af

132503255501231 has 4 divisors (see below), whose sum is σ = 133718881698600. Its totient is φ = 131287629303864.

The previous prime is 132503255501189. The next prime is 132503255501233. The reversal of 132503255501231 is 132105552305231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132503255501231 - 230 = 132502181759407 is a prime.

It is a super-2 number, since 2×1325032555012312 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132503255501233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 607813098521 + ... + 607813098738.

It is an arithmetic number, because the mean of its divisors is an integer number (33429720424650).

Almost surely, 2132503255501231 is an apocalyptic number.

132503255501231 is a deficient number, since it is larger than the sum of its proper divisors (1215626197369).

132503255501231 is a wasteful number, since it uses less digits than its factorization.

132503255501231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1215626197368.

The product of its (nonzero) digits is 135000, while the sum is 38.

The spelling of 132503255501231 in words is "one hundred thirty-two trillion, five hundred three billion, two hundred fifty-five million, five hundred one thousand, two hundred thirty-one".

Divisors: 1 109 1215626197259 132503255501231