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132504564236617 is a prime number
BaseRepresentation
bin11110001000001100011111…
…011110111000000101001001
3122101011022102220111002120001
4132020030133132320011021
5114331423321421032432
61145451431221403001
736624065424360406
oct3610143736700511
9571138386432501
10132504564236617
1139246963140a91
1212a40332569461
1358c2185742241
1424a13800dd2ad
15104bb33c359e7
hex78831f7b8149

132504564236617 has 2 divisors, whose sum is σ = 132504564236618. Its totient is φ = 132504564236616.

The previous prime is 132504564236567. The next prime is 132504564236657. The reversal of 132504564236617 is 716632465405231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 131016661955001 + 1487902281616 = 11446251^2 + 1219796^2 .

It is a cyclic number.

It is not a de Polignac number, because 132504564236617 - 211 = 132504564234569 is a prime.

It is not a weakly prime, because it can be changed into another prime (132504564236657) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66252282118308 + 66252282118309.

It is an arithmetic number, because the mean of its divisors is an integer number (66252282118309).

Almost surely, 2132504564236617 is an apocalyptic number.

It is an amenable number.

132504564236617 is a deficient number, since it is larger than the sum of its proper divisors (1).

132504564236617 is an equidigital number, since it uses as much as digits as its factorization.

132504564236617 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21772800, while the sum is 55.

The spelling of 132504564236617 in words is "one hundred thirty-two trillion, five hundred four billion, five hundred sixty-four million, two hundred thirty-six thousand, six hundred seventeen".