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13250756874973 is a prime number
BaseRepresentation
bin1100000011010010111010…
…1010000001001011011101
31201220202112000210121200011
43000310232222001023131
53214100022224444343
644103151430403221
72535223052022622
oct300645652011335
951822460717604
1013250756874973
11424968389a352
1215a0103800511
137517057ab107
1433b4a9178349
1517ea38b5a29d
hexc0d2ea812dd

13250756874973 has 2 divisors, whose sum is σ = 13250756874974. Its totient is φ = 13250756874972.

The previous prime is 13250756874959. The next prime is 13250756875079. The reversal of 13250756874973 is 37947865705231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12567684378649 + 683072496324 = 3545093^2 + 826482^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13250756874973 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13250756874899 and 13250756874908.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13250756874673) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6625378437486 + 6625378437487.

It is an arithmetic number, because the mean of its divisors is an integer number (6625378437487).

It is a 1-persistent number, because it is pandigital, but 2⋅13250756874973 = 26501513749946 is not.

Almost surely, 213250756874973 is an apocalyptic number.

It is an amenable number.

13250756874973 is a deficient number, since it is larger than the sum of its proper divisors (1).

13250756874973 is an equidigital number, since it uses as much as digits as its factorization.

13250756874973 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 266716800, while the sum is 67.

The spelling of 13250756874973 in words is "thirteen trillion, two hundred fifty billion, seven hundred fifty-six million, eight hundred seventy-four thousand, nine hundred seventy-three".